Question

Two coins are tossed simultaneously. What is the probability of event A of getting:

i) at the most one head ii) at least one tail.​

Answer 1

Answer:

at the most on head

hope it helps

Answer 2

Answer:

E6 = {HT, TH, HH} and, therefore, n(E6) = 3. Therefore, P(getting at least 1 head) = P(E6) = n(E6)/n(S) = ¾.