Question

two coins are tossed simultaneously . write the number of favourable outcomes for the following events : ( i ) getting at least one tail . ( ii ) getting no tail.​

Answer 1

Answer:

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Answer 2

Answer:

The possible outcomes when two coins are tossed together are {HH,TT,HT,TH}. Therefore, the number of possible outcomes when two coins are tossed is 4.

Now, the possible outcomes of getting at least one tail are {TT,HT,TH}, which means the number of favourable outcome is 3.

Therefore, probability P of getting at least one tail is:

P= 3/4

Hence, the probability of getting at least one tail is 3/4

Let E5 = event of getting no tail. Then,

E5 = {HH} and, therefore, n(E5) = 1.

Therefore, P(getting no tail) = P(E5) = n(E5)/n(S) = ¼.

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