Two coins are tossed together. Find the probability of one tail and one head
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E9 = {HT, TH } and, therefore, n(E9) = 2. Therefore, P(getting 1 head and 1 tail) = P(E9) = n(E9)/n(S)= 2/4 = 1/2. The solved examples involving probability of tossing two coins will help us to practice different questions provided in the sheets for flipping 2 coins.
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When two coins are tossed possible outcome are
{HH, HT, TH, TT} =4
let, E = event that getting one tail and one head
E = {HT, TH} =2
p(E)= feavourable outcome/ total no. of outcome
p(E) = 2/4 = 1/2
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