Question

Two complementary angle differ by 10degary. Find the angle.

Answer 1

Complementary angles are those angles add upto 90°. For example, 45° + 45° = 90°

Now, let's come to the question :-

Let the 1st angle be x and the 2nd angle be x + 10

A/q,

x + x + 10 = 90°

2x + 10 = 90°

2x = 90 - 10

2x = 80

x = $\dfrac{80}{2}$

x = 40

Measure of 1st angle => x => 40°

Measure of 2nd angle => x + 10 => 40° + 10 => 50°

Answer 2

Q:Two complementary angle differ by 10°. Find the angles .

solution:
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let the one complementary angle be 'x '

since , we know that the sum of two complementary angles = 90 °

then , the measure of other complementary angle will be = ( 90 - x )°

here,we have given that the difference between two complementary angles
= 10
so then ,

express the difference:
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( 90 - x ) - x = 10

90 - x - x = 10

2x = 90 - 10

2x = 80 => x = 80 ÷ 2

x = 40 ° , thus , one angle x = 40 °

therefore , the required complementary angles are x = 40 °

and 90 - x = 90° - 40° = 50°

Answer : 40° , 50°

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