Question

two complementary angles angles differ by 8'. find the angles?

Answer 1

let 1 angle be x.
then 2nd angle is 90-x
ATP,
x-(90-x)=8
x-90+x=8
2x=98
x=98/2
=49.
therefore the angles are ,
49 and 90-49 = 41.

Answer 2

Answer:

The angles are 41 and 49.

Step-by-step explanation:

Let the two complementary angles be A and 90-A.  

Given in question, A and 90-A differ by 8,

Which can be written as (90-A)-A=8

Lets solve the above equation,

Step 1:  90-A-A=8

Step 2: We know that -1-1=-2, apply same for –A and –A,

90-2A=8;

Step 3: We need to find the value of A, so keep -2A in LHS and move 90 to RHS,

Step 4: When we move the 90 the sign changed and the value become -90,

Step 5:  -2A=8-90

Step 6: Subtract RHS values, we will get -82.

Step 7: -2A=-82

Step 8: Both the side the sign are same, we can cancel the sign.

Step 9: 2A=82

Step 10:  The product value of A which is 2 moves to Dr on the RHS.

Step 11:  A=82/2

Step 12: A=41  

Step 13: So already we have one angle A which is 41 and another angle 90-A.

Step 14: Substitute the value of A in 90-A, we will get 49

Step 15: 90-A =90-41=49

Step 16:   Second angle is 49.