Question

two complementary angles are in ratio 6:3 find the measure ​

Answer 1

$let \: the \: ratio \: be\: x$

$= 6x$

$= 3x$

The sum of complementary angles is 90°

$6x + 3x = 90$

$9x = 90$

$x = 10$

$6x = 6 \times 10 = 60$

$3x = 3 \times 10 = 30$

hope it helps ❤️

Answer 2

Answer:

6x+3x=180°

9x=180°

x=180°/9

x=20°

⇒The angles are 120°,60°