Question

two complementary angles are in the ratio 7 : 11, the supplement of the larger angle is___

Answer 1

Answer:

${\boxed {\boxed{ANSWER{\ {\ }}}}}$  ${\boxed {\boxed{={\ {\ }}}}}$  ${\boxed {\boxed{70^o,110^o{\ {\ }}}}}$

Step-by-step explanation:

Let the angles be $7x$ and $11x$

They are supplementary angles, their sum is $180^o$

WE KNOW THAT LiNEAR EQAUTION IS

$\Longrightarrow7x + 11x = 180^o\\\\\Longrightarrow 18x = 180^o\\\\\Longrightarrow x = \frac{8}{180{\rm }_{}}\\\\\Longrightarrow x = 10$

Now value of $x$ = $10^o$

Now the substitute the values

Angle of 7 = 7 x 10 = $70^0$

Angle of 11 = 11 x 10 = $110^o$