Question

Two Complementary angles are such that 2 times the measure of 1 is equal to 3 times the measure of the other. The measure of smaller angle is...?

Answer 1

Answer:

Let the measure of one angle be X

then, the measure of its complement is 90° - X

ATQ,

2x = 3(90°-x)

= 2x = 270° -3x

= 2x+3x = 270°

= 5x = 270°

= X= 54°

=> 90°-x

=> 90°-54°

=> 36°

Hence, the measure of smaller angle is 36°.

Answer 2

$\huge \underline \bold \red {\: Question.}$

Two Complementary angles are such that 2 times the measure of 1 is equal to 3 times the measure of the other. The measure of smaller angle is...?

$\huge\orange{\underline {\mathscr{A}}} \orange{\underline {\mathbb {\green{ns}}}} \orange{\underline {\mathfrak \red{we}}}\orange{\underline \bold \pink{r}}$

Let the measure of one angle be X

Let the measure of one angle be X then, the measure of its complement is 90° - X

ATQ,

2x = 3(90°-x)

= 2x = 270° -3x

= 2x+3x = 270°

= 5x = 270°

= X= 54°

=> 90°-x

=> 90°-54°

=> 36°

Hence, the measure of smaller angle is 36°.

Thanks..