Question

Two complementary angles are such that one is 14° more than 3 times the other.What is the measure of the larger angle?

Answer 1

Answer:    Let the smaller angle be x°

Larger angle =3x+14°

ATQ

x+3x+14 =90

4x +14=90

4x=76

x=19

The larger angle =3x+14

=3*19+14

=57+14

=71

Answer 2

Answer:

Let one of the angle be X.

Then, the other angle be 3x + 14°.

We know that,

sum of complementary angle = 90°

=> X + 3x + 14° = 90°

=> 4x = 90° - 14°

=> x = 76/4

=> x = 19°

therefore,

largest angle= 3x + 14°

= 3*19 +14°

= 57° + 14°

= 71°