Question

Two complementary Angles are such that twice the measure of the one is equal to three times the measure of the other.The larger of the two measures ?

Answer 1

Hola

∆ Ratio of complimentary angles = ( 2 : 3 )

=> We can say, the angles are : 2x , 3x

$= > 2x + 3x = {90}^{0}$

$= > 5x = {90}^{0}$

$= > 2x = \frac{2}{5} ({90}^{0} )$

$= > 2x = {36}^{o}$

And hence, one angle = 2x = 36° and the other is : 54°

Answer 2

Let the first angle be x

Second angle be =2x

Now,

x+2x=90°

3x=90°

x=90/3

x=30

Therefore the first complement angle is 3x