Math, asked by vandanakr567, 22 days ago

Two complementary angles are such that twice the measure of the one is equal to three times the measure of the other. The larger of the two measure

Answers

Answered by mahakulkarpooja615
0

Answer:

54^{0}

Step-by-step explanation:

  • Two complementary angles are such that twice the measure of the one is equal to three times the measure of the other.
  • We know that complementary angles are the two angles whose sum of measures is 90^{0}.
  • Let, the two complementary angles be x and (90-x) respectively.
  • According to given condition, the equation of measures of angles becomes,
  • 2x = 3(90-x)

           ∴ 2x = 270 - 3x

    ∴ 2x + 3x = 270

           ∴ 5x = 270

             ∴ x = \frac{270}{5}

             ∴ x = 54^{0}

  • ∴ The two complementary angles are 54^{0} and (90 - 54)^{0}  = 36^{0}.
  • ∴ The larger angle of the two angles is 54^{0}.

Answered by junaida8080
0

Given,

The two complementary angles such that twice the measure of one is equal to thrice the measure of other.

The angles are said to be complementary, the sum of their angles should be 90^{0}.

Let the two angles be x^{0} and (90-x)^{0}

The given condition is

2x=3(90-x)

2x=270-3x

Move -3x from RHS to LHS

We get,

2x+3x=270

5x=270

x=54^{0}

One of the complementary angles is 54^{0}

The other angle is

90-54

36^{0}

The other complementary angle is 36^{0}

The two complementary angles are 54^{0} ,36^{0}

Therefore, the largest angle among the two angles is 54^{0}

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