Two complementary angles are x 5 and 3x-7 find the value of x
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hyy....
as we know .... if sum of two angles is 90° then it's called a complementary angle ...
so a/q ,
5x + ( 3x - 7 ) = 90°
8x - 7 = 90°
8x = 90 + 7
8x = 97
x = 97 / 8
...
now, first angle 5x = 5 × 97/ 8 = 60. 62°
and the second angle = 3x - 7 = 3 × 97/ 8 - 7 = 29.38° ...
hope this helps !
as we know .... if sum of two angles is 90° then it's called a complementary angle ...
so a/q ,
5x + ( 3x - 7 ) = 90°
8x - 7 = 90°
8x = 90 + 7
8x = 97
x = 97 / 8
...
now, first angle 5x = 5 × 97/ 8 = 60. 62°
and the second angle = 3x - 7 = 3 × 97/ 8 - 7 = 29.38° ...
hope this helps !
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