two complementary angles differ by 6 degrees.find the angles
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Answered by
10
let the angles be x and x+6
A/Q
(x)+(x+6)=90°
→2x+6 =90°
→2x = 84°
→x = 42°
→x+6= (42+6)°= 48°
∴the angles are 42° and 48°
A/Q
(x)+(x+6)=90°
→2x+6 =90°
→2x = 84°
→x = 42°
→x+6= (42+6)°= 48°
∴the angles are 42° and 48°
Answered by
4
Thelet the complementary angles be x and y then,
x+y=90°....1
difference of complementary angles is 6° then,
x-y=6°...2
then on solving eqn 1 & 2 we get,
x+y-(x-y)=90-6
=>2y=84
=>y=42°
Then, x=90-42=48°
mark my answer as brainliest
x+y=90°....1
difference of complementary angles is 6° then,
x-y=6°...2
then on solving eqn 1 & 2 we get,
x+y-(x-y)=90-6
=>2y=84
=>y=42°
Then, x=90-42=48°
mark my answer as brainliest
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