two complementary angles differ by 8° . find the angels
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Let the first angle be x°
the second angel be (90-x)°
x°-(90-x)°=8°
x°-90°+x°=8°
2x°=98°
x°=49°
(90-x)°=90-49=41°
Answered by
2
Step-by-step explanation:
let 1 angle be x
then 2nd angle is 90-x
ATP,
x-(90-x) = 8
x-90+X= 8
2x=98
X= 98/2
= 49
therefore the angles are 49 and 990-49 = 41
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