Question

Two complementary angles differ by 8°. Find the angles.​

Answer 1

let 1 angle be x.

then 2nd angle is 90-x

ATP,

x-(90-x)=8

x-90+x=8

2x=98

x=98/2

=49.

therefore the angles are ,

49 and 90-49 = 41.

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Answer 2

Answer:

let the angle be x.

then,

90-x+x = 8 °

90°-2x. = 8°

2x. = 8°+90°

2x. = 98°

x. = 98°/2

x. = 49°

1st angle = x = 49°

2nd angle= 90°- x

= 90°-49°

= 41°

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