Question

two complementary angles differs by the 42 degree find the angle

Answer 1

Let one angle be x the other is x-42

X+X-42=90

2x-42=90

2x=132

x=66

One angle is 66

Another angle is 14

Answer 2

Answer:

$\bf let \: one \: angle \: be \: x$

$\bf then$

$\bf 2n d\: angle \: will \: be \: x + 42$

$\bf we \:know \: that$

$\bf sum \: of \: measures \: of \:$

$\bf complementary \: angle \: is \: 90$

$\bf now$

$\bf⇒x + x + 42 = 90$

$\bf⇒2x + 42 = 90$

$\bf⇒2x = 90 - 42$

$\bf⇒2x = 48$

$\bf⇒x = \frac{48}{2}$

$\bf⇒x = 24$

$\therefore therefore$

$\bf the \: smaller \: angle = 24$