Question

Two complementary angles of (3x+8)and (4x-2) find x

Answer 1

two angles are (3x+8) n (4x-2)

we know that,

sum of complementary angles is 90° according to question,

3x+8+4x-2=90°

7x=84

x=12

now, the angles are-

3x+8=44°

4x-2=46°

hence , the two angles are 44°and 46°