Question

two complementory angles are such that two times the measure of one is equal to three times the measure of the other . The measure of the smaller angle is 45, 30,36 , none of these​

Answer 1

Answer:

Let the complementary angles be x and (90

Let the complementary angles be x and (90 o

Let the complementary angles be x and (90 o −x).

Let the complementary angles be x and (90 o −x). Then, 2x=3(90

Let the complementary angles be x and (90 o −x). Then, 2x=3(90 o

Let the complementary angles be x and (90 o −x). Then, 2x=3(90 o −x)

Let the complementary angles be x and (90 o −x). Then, 2x=3(90 o −x)⇒ 2x=270

Let the complementary angles be x and (90 o −x). Then, 2x=3(90 o −x)⇒ 2x=270 o

Let the complementary angles be x and (90 o −x). Then, 2x=3(90 o −x)⇒ 2x=270 o −3x ⇒ 5x=270

Let the complementary angles be x and (90 o −x). Then, 2x=3(90 o −x)⇒ 2x=270 o −3x ⇒ 5x=270 o

Let the complementary angles be x and (90 o −x). Then, 2x=3(90 o −x)⇒ 2x=270 o −3x ⇒ 5x=270 o

Let the complementary angles be x and (90 o −x). Then, 2x=3(90 o −x)⇒ 2x=270 o −3x ⇒ 5x=270 o ⇒ x=

Let the complementary angles be x and (90 o −x). Then, 2x=3(90 o −x)⇒ 2x=270 o −3x ⇒ 5x=270 o ⇒ x= 5

Let the complementary angles be x and (90 o −x). Then, 2x=3(90 o −x)⇒ 2x=270 o −3x ⇒ 5x=270 o ⇒ x= 5270

Let the complementary angles be x and (90 o −x). Then, 2x=3(90 o −x)⇒ 2x=270 o −3x ⇒ 5x=270 o ⇒ x= 5270 o

Let the complementary angles be x and (90 o −x). Then, 2x=3(90 o −x)⇒ 2x=270 o −3x ⇒ 5x=270 o ⇒ x= 5270 o

Let the complementary angles be x and (90 o −x). Then, 2x=3(90 o −x)⇒ 2x=270 o −3x ⇒ 5x=270 o ⇒ x= 5270 o

Let the complementary angles be x and (90 o −x). Then, 2x=3(90 o −x)⇒ 2x=270 o −3x ⇒ 5x=270 o ⇒ x= 5270 o =54

Let the complementary angles be x and (90 o −x). Then, 2x=3(90 o −x)⇒ 2x=270 o −3x ⇒ 5x=270 o ⇒ x= 5270 o =54 o

Let the complementary angles be x and (90 o −x). Then, 2x=3(90 o −x)⇒ 2x=270 o −3x ⇒ 5x=270 o ⇒ x= 5270 o =54 o

Let the complementary angles be x and (90 o −x). Then, 2x=3(90 o −x)⇒ 2x=270 o −3x ⇒ 5x=270 o ⇒ x= 5270 o =54 o ∴ The two angles are 54

Let the complementary angles be x and (90 o −x). Then, 2x=3(90 o −x)⇒ 2x=270 o −3x ⇒ 5x=270 o ⇒ x= 5270 o =54 o ∴ The two angles are 54 o

Let the complementary angles be x and (90 o −x). Then, 2x=3(90 o −x)⇒ 2x=270 o −3x ⇒ 5x=270 o ⇒ x= 5270 o =54 o ∴ The two angles are 54 o , 36

Let the complementary angles be x and (90 o −x). Then, 2x=3(90 o −x)⇒ 2x=270 o −3x ⇒ 5x=270 o ⇒ x= 5270 o =54 o ∴ The two angles are 54 o , 36 o

Let the complementary angles be x and (90 o −x). Then, 2x=3(90 o −x)⇒ 2x=270 o −3x ⇒ 5x=270 o ⇒ x= 5270 o =54 o ∴ The two angles are 54 o , 36 o

Answer 2

Answer:

none of these

Step-by-step explanation:

let one angle be x

complementary angle= 90-x

2x= 3(90-x)

2x= 270-3x

5x=270

x=54