Question

Two complementry angles differ by 42° then the smallest angle is

Answer 1

Answer:

$\bf let \: one \: angle \: be \: x$

$\bf another \: angle \: will \: be \: x + 42$

$\bf we \: know \: that$

$\bf sum \: of \: measures \: of \: complementary$

$\bf⇒angle \: is \: 90$

$\bf then$

$\bf ⇒x + x + 42 = 90$

$\bf⇒2x + 42 = 90$

$\bf⇒2x = 90 - 42$

$\bf⇒2x = 48$

$\bf⇒x = \frac{48}{2}$

$\bf⇒x = 24$

$\therefore therefore$

$\bf⇒1st \: angle \: = 24$

$\bf⇒2nd \: angle \: = 24 + 42$

$\bf⇒2nd \: angle \: = 66$

$\bf then$

$\bf⇒the \: smallest \: angle = 24$

Answer 2

Given that:-

➤let on angle be x

➠another angle will be x + 42

⇨we know that

➠sum of measures of complementary

⇒angle is 90

➤then

⇒x + x + 42 = 90

⇒2x + 42 = 90

⇒2x = 90 - 42

⇒2x = 48

⇒x = 48/2

⇒x=24

➤therefore

⇒1st angle = 24

⇒2nd angle = 24+42

⇒2nd angle = 66

➤Now

⇨the smallest angle = 24