Two compounds A and B react with each other in the presence of a dehydrating agent to produce an
ester. Both react with Na to evolve hydrogen gas. On reaction with Na2CO3 only A evolves CO2.
Identify the functional groups present in A and B giving reason for your answer.
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ESTERIFICATION REACTION:
Ethanoic acid reacts with Ethanol on warming in presence of a few drops of conc. H2SO4 to form a sweet smelling ester.
CH3COOH + C2H5OH -------------->CH3COOC2H5 + H2O
SO A AND B ARE ETHANOIC ACID and ETHANOl.
Both compounds A and B react with sodium metal to evolve Hydrogen gas.
Chemical Reaction:
2C2H5OH+2Na ----->2C2H5O⁻Na⁺ + H2
Compound A reacts with Na2CO3 TO EVOLVE CO2 GAS
2CH3COOH + Na2CO3 -----> 2CH3COONa + CO2 +H2O
So from the above chemical reaction we can see clearly compound A belongs to carboxylic acid functional group [COOH] and compound B belongs to alcohol functional group[OH].
Ethanoic acid reacts with Ethanol on warming in presence of a few drops of conc. H2SO4 to form a sweet smelling ester.
CH3COOH + C2H5OH -------------->CH3COOC2H5 + H2O
SO A AND B ARE ETHANOIC ACID and ETHANOl.
Both compounds A and B react with sodium metal to evolve Hydrogen gas.
Chemical Reaction:
2C2H5OH+2Na ----->2C2H5O⁻Na⁺ + H2
Compound A reacts with Na2CO3 TO EVOLVE CO2 GAS
2CH3COOH + Na2CO3 -----> 2CH3COONa + CO2 +H2O
So from the above chemical reaction we can see clearly compound A belongs to carboxylic acid functional group [COOH] and compound B belongs to alcohol functional group[OH].
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