Question

Two computers a and b are to be marketed. a salesman who is assigned the job of finding customers for them has 60% and 40% chances, respectively, of succeeding in case of computer a and


b. the two computers can be sold independently. given that he was able to sell at least least one computer, what is the probability that computer a has been sold?

Answer 1

is my photo is correct

Answer 2

What is the probability that computer A has been sold?

Given,

Let the event of the salesman selling computer A be 'A' and selling computer B be 'B'.

P (A) = 60% = 6/10

P(B) = 40% = 4/10

He sells at least one computer.

To Find,

Probability that computer A has been sold

Solution,

Probability that at least one computer has been sold = P(A∪B)

P(A∪B) = P(A) + P(B) - P(A∩B)

= 0.6 + 0.4 - 0.24

= 0.76

Probability that A has been sold given that at least one computer has been sold can be written as P(A | (A∪B))

= [P(A∩(A∪B))] / P((A∪B))

= P(A) / P(A∪B)

= 0.6/0.76

P(A | (A∪B)) = 0.789

∴ The probability that computer A has been sold IS 0.789.

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