Two computers were purchased for rupees16000 each.one was sold at a gain of 5% and the other at a loss of 4%.find the overall gain or loss% in
The whole transaction
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Answered by
2
Answer:
CP of computer=16000 rs
no of computer= 2
total cost= 2×16000=32000rs
first is sold at 5% gain ,
gain= (5×16000)/100=800 rs
SP of first computer=800+16000=16800 rs
2nd has loss of 4% ,
loss=(4×16000)/100=640 rs
SP of 2nd computer= 16000-640=15360rs
total CP= 32000 rs
total SP= 15360+16800=32160rs
as SP>CP , there is profit,
profit= 32160-32000= 160
profit %=(160×100)/32000= 0.5%
Answered by
0
Answer:
I) CPof the Ist Computer = Spx loo/100+Gain.%=16000x100/105
= Rs15238
2 ) Cp of the 2nd computer = spx 100 / 100-loss%=16ooox loo/96
=Rs16667
Total. Sp=16ooo x2 = 32ooo
Total CP = 15238+16667=31905
Sp>CP, Gain=32000-31905= Rs95
Gain%=95/31905x100 = 0.3%
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