Two concave lens of focal length are combined ,find the resultant of focal length
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if P be the equivalent power of a lens then P=p1 +p2
so here
1/f=(1/f1)+(1/f2)
so 1/f=(f1 +f2)/f1.f2
so f= f1.f2/(f1+f2)
so here
1/f=(1/f1)+(1/f2)
so 1/f=(f1 +f2)/f1.f2
so f= f1.f2/(f1+f2)
Anibh70:
It 's very helpful
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