Question

Two concentric circle are of raddi 5cm and 3cm. Find the
length of the chord of the larger circle which touches the
smaller circle​

Answer 1

Answer:

Let O be the centre of the concentric circle of radii 5 cm and 3 cm respectively. Let AB be a chord of the larger circle touching the smaller circle at P.  

Then

AP=PB and OP⊥AB

Applying Pythagoras theorem in △OPA, we have

OA  

2

=OP  

2

+AP  

2

 

⇒25=9+AP  

2

 

⇒AP  

2

=16⇒AP=4 cm

∴AB=2AP=8 cm

Step-by-step explanation:

Answer 2

SEE THE ATTACHMENT

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