Two concentric circle having radii 17
and 8 are given. The chord of the circle with larger radius touches the circle with smaller radius. Find the length of the chord.
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According to the Question,
OC = radius of smaller circle = 8 cm.
OC = radius of smaller circle = 8 cm.OA = radius of larger circle = 17 cm.
AB = chord of larger circle
OC ⊥ AB
OC ⊥ AB∴ AC = CB
From ∆ OAC
AC = √OA² - OC² = √17² - 8²
AC = √(17 + 8)(17 - 8)
AC = √25 × 9 = 5 × 3 = 15 cm.
∴ AB = 2AC = 30 cm.
AnSwEr = 30 cm
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