Question

two concentric circles are 13 cm and 8 cm ab is the diameter of the bigger circle and BD is the tangent to a smaller circle touching it at the and intersecting the larger circle at P on producing find the length of AP​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:16

Step-by-step explanation:

Construction: OD is drawn

Solution:

Since ab is diameter of bigger circle,

Therefore apb= 90° (angle on a semicicle)

Now,

odb= 90°(radius drawn to the point of contact of a tangent )

Therefore in triangle odb and apb, we have

Apb=Odb(each 90°)

B=B(common angle)

Therefore odb is similar to apb

Therefore,

Ap/Ab=Od/Ob

Implies,Ap/2Ob=8/Ob

Implies,Ap=8*2=16