Question

two concentric circles are of radii 17 centimetre and 18cm then find the length of the chord of the larger circle which touches the smaller circle​

Answer 1

{ Tanglent is perpendicular to the radius of the circle at the point of contact }

angle AOC is 90°

In ∆ OAC,

• AC² + OC² = AO² ( By Pythagoras theorem )
• AC = √AO² + OC²
• AC = √(18 cm)²- (17 cm)²
• AC = √35 cm

[ In two concentric circles, the chord of the bigger circle that touches the smaller circle is bisected at the point of contact with the smaller circle ]

Therefore, AB = 2 × AC = 2 × √35cm = 2√35 cm.

Therefore, the lenth of the chord is 2√35 cm.

Hope this helps you.

Thank you for your question.

Mark me as brainleist.