two concentric circles are of radii 26 cm and 10 cm find the length of the chord of the bigger circle which touches the smaller circle....ans this
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Hey mate ,
let r be 26 cm
and R be 10 cm
A is centre of both circles
AB perpendicular to DC
as radius from centre is perpendicular to the tangent at the point of contact
Thus In ∆ ABC
R^2 + BC ^2 = r^2
BC^2 = 26^2 - 10^2
BC^2 = 676-100
BC^2 = 576
BC = √576
BC = 24 cm
Similarly, DB = BC
Thus DC = 2BC
DC = 24×2
DC = 48 cm = Chord length
Hope you find it helpful!!!
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I have given the answer in images ...
bcz it was hard to type i have cliped a clear
picture and you can have a view on it...
Thank you.
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