Two concentric circles are of radii 26 cm and 24 cm. find the chord of the larger circle which touches the smaller circle
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2
Step-by-step explanation:
let r be 26 cm
and R be 10 cm
A is centre of both circles
AB perpendicular to DC
as radius from centre is perpendicular to the
tangent at the point of contact
Thus In A ABC
R^2 + BC ^2=r^2
BC^2 = 26^2 - 10^2
BC^2 = 676-100
BC^2 = 576
BC = √576
BC = 24 cm
Similarly, DB = BC
Thus DC = 2BC
DC = 24×2
DC = 48 cm = Chord length
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Answered by
4
Answer:
49cm
Step-by-step explanation:
the radius of the chord
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