Question

two concentric circles are of radii 26cm and 10cm. find the length of the chord of the larger circle which touches the smaller circle​

Answer 1

Answer:

let r be 26 cm

and R be 10 cm

A is centre of both circles

AB perpendicular to DC

as radius from centre is perpendicular to the tangent at the point of contact

Thus In ∆ ABC

R^2 + BC ^2 = r^2

BC^2 = 26^2 - 10^2

BC^2 = 676-100

BC^2 = 576

BC = √576

BC = 24 cm

Similarly, DB = BC

Thus DC = 2BC

DC = 24×2

DC = 48 cm = Chord length

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Answer 2

Answer:

length of half chord = √26^2 -10^2

=√576 =24

therefore length of full chord = 2 × 24=48cm