Two concentric circles are of radii 5 cm and 3 cm. Find the length of the
chord of the larger circle (in cm) which touches the smaller circle.
[CBSE 2012, '14)
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Answer:
first lets recall a few things
the tangent at any point of a circle is perpendicular to the radius through the point of contact. (1)
the perpendicular from the center of the chord bisects the chord. (2)
plzz refer to the attachment also.
let O be the center common to the two circles . join OM and OP
PQ is the chord of the larger circle (in cm) which touches the smaller circle.
then,
by (1)
ΔOMP is right angled so
OP²=OM²+PM² pythagoras ofcourse
5²=3²+PM²
PM²=5²-3²=16
then PM=√16=4
now by (2)
PM=MQ=4
so PM+MG=PQ=4+4=8cm
hope this helps...
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