Question

two concentric circles are of radii 5cm and 3cm find the length of the chord of the larger circles which touches the smaller circles​

Answer 1

AB= 8 cm

Step-by-step explanation:

Here OC is the radius and AB is the tangent to the smaller circle.

Hence OC is perpendicular bisector of AB.

In triangle OCB,

${CB} ^{2} = {OB}^{2} - {OC}^{2} \\ = {5}^{2} - {3}^{2} \\ = 16 \\ CB = 4cm$

AB =2 x CB

= 2 x 4 = 8cm

Answer 2

heyy mate

hope it is helpful for you...