two concentric circles are of radii 6.5 cm and 5 cm and the find the length of the chord of the larger circle which touches the smaller circle
with diagram
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Step-by-step explanation:
Let O be the center of circle. Draw two concentric circles are of radii 6.5cm and 2.5cm, and
$$AB =$$ Chord of the larger circle which touches the smaller circle at C.
From Figure:
OC= radius =2.5cm
OA=6.5cm
AC=CB
OC⊥AB and OC bisects AB at C.
In right ΔOPT,
By Pythagoras Theorem:
OA
2
=OC
2
+AC
2
6.5
2
=2.5
2
+AC
2
42.25=6.25+AC
2
AC=6
Length of chord of a circle =AB=2×AC=2×6=12cm.
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