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Two concentric circles are of radii 7 cm and rcm respectively, wherer >7.Achord of the larger
circle, oflength 48 cm, touches the smaller circle. Find the value of r
Answers
Answered by
1
Answer:
25
Step-by-step explanation:
chord touches smaller circle
so it becomes tangent for smaller one
so it divides half and angle with 90 degrees
hence in a right angle triangle one side is 7 CM and another one is half of chord length 24 CM and hypotenuse is r CM
so
sqrt(r^2-7^2)=24^2
r=25
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