two concentric circles are of radius 10 cm and 8 cm to copy and RP and RQ are two tangents to the two circles from R if the length of RP is 24 find the length of a RQ
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Step-by-step explanation:
Let the circles have common centre O. Let RP and RQ be the tangents to the larger and smaller circle respectively. Join OP, OQ, OR. By Pythagoras Theorem, OR2 =OP2+PR2 , OR2=102+242, OR2=100+576=676, OR=26. In the right triangle OQR, RQ2=OR2-OQ2=262-82=676-64=612. RQ=sq.root 612 = 6 root 17. This is the Answer for the above question.
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