Two concentric circles are of the radii 5cm and 3cm. Find the length of the cord of the larger circle which touches the smaller circle.
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Let O be the centre of the concentric circle of radii 5 cm and 3 cm respectively. Let AB be a chord of the larger circle touching the smaller circle at P.
Then,
AP = PB and OP⊥AB
Applying Pythagoras theorem in △OPA,
We have,
OA² = OP² + AP²
⇒25 = 9 + AP²
⇒ AP² = 16
⇒ AP = 4 cm
∴AB = 2AP = 8 cm
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