two concentric circles have a common centre o. The chord ab of the bigger circle touches the smaller circle at p. if op=3cm and ab=8cm, then find the radius of the bigger circle
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Two concentric circles have a common centre O . The chord AB to the larger circle touches the smaller circle at P . If OP=3 cm and AB=8 cm, how would one find the radius of the larger circle?
Since chord AB is tangent to smaller circle at P , then radius OP is perpendicular to line segment AB at point P .
Let r= radius of larger circle.
Since points A and B are on larger circle, then OA=OB=r .
Since △OAB is isosceles (OA=OB) , then perpendicular bisector OP bisects AB .
AB=8 cm ⟹AP=BP=4 cm
Using Pythagorean theorem, we get:
r2=32+42
r2=25
r=5
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Here is the solution..
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