Question

Two concentric circles of centre o are of radii 5cm and 3 cm. from an external point p tangents pa and pb are drawn to these circles. if ap = 12 cm find bp

Answer 1

Answer:

Step-by-step explanation:

IN TRIANGLE PAO , PA=12CM

PO=?

AO=5CM  

PO^2 = PA^2+AO^2

PO^2 = 12^2 + 5^2

144+25

PO^2 = 169

IN TRIANGLE POB , B=90°

PO=13CM from above

PB=?

BO=3CM

USE PYTH THEOREM

PO^2=PB^2+BO^2

13^2=PB^2+3^2

13^2-3^2=PB^2

169-9=160

= PB^2=160 , PB= √160

THEREFORE , BP=√160

Answer 2

Answer:

I have solved in my own way.....

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