Question

Two concentric circles of radii 10 cm and 5 cm are drawn. Find the length of
the chord of the longer circle, which touches the smaller circle.​

Answer 1

Answer:

R = 10 cm

r = 5 cm

Length of the chord = 2_/(R^2 - r^2)

=> Length of chord = 2_/(100 - 25)

=> Length of chord = 2_/75

=> Length of chord = 10_/3 cm

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Answer 2

Answer: 10√3

Step by step explanation:

Given:

Two concentric circles are of radii 10 cm and 5 cm.

To find: Chord of the longer circle, which touches the Smaller circle.

Solution:

Let the chord of longer circle be R

let the chord of smaller circle be r

So, R = 10 cm and r = 5 cm.

Length of the chord = 2 × √( R² - r² )

= 2× √( 10² - 5² )

= 2 × √(100 - 25)

= 2 × √75

= 2√75

= 10√3

Thus, answer: Chord of the longer circle, which touches the Smaller circle Is 10√3 cm.