Question

Two concentric circles of radii a and b a greater than b are given find the length of the chord of the larger circle which touches the smaller circle

Answer 1

your answer is √2(a2 - b2 )

Answer 2

Hey mate!!

Radius of larger Circle = b

Radius of smaller Circle = a

ATQ

Let, length of chord be PQ which touches the smaller Circle at R

Angle ORP = 90°(tangent & radius perpendicular to each other on the point of contact)

So,

By using PGT

PO² = RO² + PR²

a² = b² + PR²

PR = $\sqrt{a^2 - b^2}$

PR = $\frac{1}{2}$ PQ

Thus length of chord PQ = 2PR

PQ = $\boxed{2\sqrt<u>{a^2 - b^2</u>}}$

Hope it helps you!

#Be Brainly