Two concentric circles of radii a and b (a > b) are given. Find the
length of the chord of the larger circle which touches the smaller
carde.
ICBSE 2015
o be the common centre of
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Angle OEC=90(tangent and radius at point of contact are perpendicular)
by Pythagoras theorem
OC^2=OE^2+CE^2
a^2=b^2+CE^2
√(a^2-b^2)=CE
CD=2CE[perpendicular drawn from centre bisect the chord]
CD=2√(a^2-b^2)
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