Two concentric circles of radii a and b (a > b) are given. Find the length of the chord of the larger circle
which touches the smaller circle.
Answers
Answered by
1
Step-by-step explanation:
Correct option is
C
2
a
2
−b
2
Chord of larger circle will be the tangent to smaller circle.
Thus, OC is perpendicular to chord AB and bisects it.
By Pythagoras theorem, in right triangle ACO,
OA
2
=OC
2
+CA
2
a
2
=b
2
+CA
2
(a
2
−b
2
)
=CA
AB=2CA [perpendicular drawn from centre bisect the chord]
AB=2
(
a
2
−b
2
)
option C will be the answer.
solution
Answered by
0
Refer to the attachment.
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