Question

two concentric circles of radii x and y are given , where x>y . Find the chord of the larger circle which touches the smaller circle

Answer 1

Here u go

If you like it follow me and punch the brainiest button in the face

Answer 2

The length of the chord is √2a²-b²

Radii of two circles = x and y

Let the centre of concentric circles be = O

Chord of the larger circle which is also a tangent to smaller circle = PQ

Let OR = a and OQ = b

∠ORQ = 90

OR ⊥ PQ ( Perpendicular drawn from centre to the chord bisects the chord)

PR = QR = PQ/2

In ΔORQ

OQ² = OR² + QR²

QR² = OQ² - OR² = a² - b²

QR² = √a² - b²

PQ = 2QR = √2 a² - b²

Therefore, the length of the chord is √2a² - b²