two concentric circles of radii x and y are given where X > Y find the chord of the larger circle which touches the smaller circle
devika1792:
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Thank you for asking this question. Here is your answer:
∠OEC = 90°
Now we will use the Pythagoras theorem:
(OC)² = (OE)² + (CE)²
x² = y² + (CE)²
CD = 2 CE (⊥ from center bisect the chord)
CD = 2√x²-y²
If there is any confusion please leave a comment below.
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