two concentric circles with radii a and b (a>b)are given .find the length of the chord of the larger circle which touches the smaller circle
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Chord of larger circle will be the tangent to smaller circle.
Thus, OC is perpendicular to chord AB and bisects it.
By Pythagoras theorem, in right triangle ACO,
OA2=OC2+CA2
a2=b2+CA2
(a2−b2)=CA
AB=2CA [perpendicular drawn from centre bisect the chord]
AB=2(a2−b2)
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