Two concentric conducting spheres of radii R and 2R are carrying charges Q and _2Q respectively.If the charge on inner sphere is doubled the potential difference between the two spheres will
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Hope u know that potential differences (v) of sphere is q/4pi€R
here q=charge ,R=radius
for inner sphere q/4pi€R
for outer sphere -2q/4pi€2R=-q/4pi€R
substrate v inner sphere to outer we get
v differences =2q/4pi€R
now if charge is double of inner sphere then
v=2q/4pi€R
now subt v inner to outer
we get 2q/4pi€R-(-q/4pi€R)=
3q/4pi€R
that is the answer
mark me a brainliest if i got answer
here q=charge ,R=radius
for inner sphere q/4pi€R
for outer sphere -2q/4pi€2R=-q/4pi€R
substrate v inner sphere to outer we get
v differences =2q/4pi€R
now if charge is double of inner sphere then
v=2q/4pi€R
now subt v inner to outer
we get 2q/4pi€R-(-q/4pi€R)=
3q/4pi€R
that is the answer
mark me a brainliest if i got answer
Answered by
0
Answer:
Hope u know that potential differences (v) of sphere is q/4pi€R
here q=charge ,R=radius
for inner sphere q/4pi€R
for outer sphere -2q/4pi€2R=-q/4pi€R
substrate v inner sphere to outer we get
v differences =2q/4pi€R
now if charge is double of inner sphere then
v=2q/4pi€R
now subt v inner to outer
we get 2q/4pi€R-(-q/4pi€R)=3q/4pi€Rthat is the answer
mark me as brainliest !!!
thanks plz
Explanation:
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