Question

Two concentric conducting spherical shells of radii R and 2R are carrying charges q and 2q respectively.Both are now connected by a conducting wire. The amount of charge flown through the wire is


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Answer 1

$\huge{\underline{\tt{\Red{Answer-}}}}$

The amount of charge flown through the wire is Zero .

$\huge{\underline{\tt{\blue{Explanation-}}}}$

The amount of charge flown through the wire is change in electric potential

When shells are connected, charge on inner shell will be transferred to the outer shell.

so, V = potential

$V_i = initial \ potential$

$V_f = final \ potential$

$change \ in \ potential \ \Delta V = V_f - V_i$

$V_i = \dfrac {KQ}{2R}+ \dfrac {2KQ}{2R} = \dfrac {3KQ}{2R}$

$V_f= \dfrac {3KQ}{2R}$

$V_i= V_f\\so \ \Delta V = 0$