Question

Two condenser of 2uF and 4uF are connected in series .The p.d across them is 1200 volt.The p.d across 2uF is

Answer 1

Answer:

Potential difference across $2\mu F$ will be 800 volt

Explanation:

We have given that two condensers are connected in series having capacitance $2\mu F\ and\ 4\mu F$

It is given that potential difference across them is V= 1200 volt

We have to find the potential difference across $2\mu F$

For finding potential difference across $2\mu F$ we have to use voltage divider rule

So according to voltage divider rule potential difference across $2\mu F$ will be

$V_1=V\times \frac{C_2}{C_!+C_2}$

$V_1=1200\times \frac{4}{2+4}=800 volt$

So potential difference across $2\mu F$ will be 800 volt