Question

Two condenser of capacity 2 F and 3 F are connected in series and potential difference of 100 volt is maintained across them. Calculate p.d. and energy stored in each capacitor. ​

Answer 1

Explanation:

Equivalent capacitance of the circuit

C

eq

1

=

C

1

1

+

C

2

1

+

C

3

1

∴

C

eq

1

=

20

1

+

30

1

+

15

1

⟹ C

eq

=6.67 μF

Thus charge flowing through the circuit Q=C

ee V=6.67μ×90=600 μC

Potential difference across C /2

V /2 = C /2

Q = 30/600 =20 volts

Energy stored in C/2

E/2 = 2/1

C /2 V 2/2 = 2/1×30μ×(20) 2 =6×10 −3 J