Question

Two condensers each of 4μF capacitance are joined in parallel.The resultant capacitance of the combination is​

Answer 1

Answer:

resultant capacity is 8 micro farad

Explanation:

in parallel combination the effective capacitance

C= C1+C2 = 4+4 = 8 micro farad

Answer 2

Given:

Two condensers each of 4μF capacitance are joined in parallel.

To find:

Resultant capacitance?

Solution:

Now, we know that for parallel combination of capacitors:

$\therefore C_{eff} = C_{1} + C_{2}$

$\implies C_{eff} = 4 + 4$

$\implies C_{eff} = 8 \: \mu F$

So, net capacitance is 8 micro-F.